Tap A alone can fill the tank in = 10 hours. Tap B alone can fill the tank in = (8/1) × 5 = 40 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 8 × (5/2) = 20 Taking LCM of 10, 40 and 20 = 40 Efficiency of Tap A = 4 Efficiency of Tap B = 1 Efficiency of Taps (A + B +C) = 2 Efficiency of Taps (A +C) = 2 – 1 = 1 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (40/1) = 10 hours
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