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Total capacity of tank = 60 {LCM of 20 and 15} Efficiency of pipe 'Q' = 60/20 = 3 units per hr Efficiency of pipe 'R' = 60/15 = 4 units per hr Required time = 60/7 = 8(4/7) hrs Hence, option c.
111.89 × 4.12 – 504.04 ÷ 2.12 = 170.12 + ?
11.11% of (123.45 + 234.56) + 10.01³ - (5.05 of 7.07) = ? of (88.88 - 33.33)
15.2 x 1.5 + 258.88+ ? = 398.12 + 15.9
6940 ÷ 28 ÷ 7 = ?
Solve the given equation for ?. Find the approximate value.
(124.85% of 639.77 – 39.85% of 450.21) × (√224.85 ÷ √35.96) = ?
...{(22.22 2 + 6.06 3 ) ÷ 15.15} × 3.03 = ? – 55.05 × 4.04
15.08% of (133.13 + 146.928) + 8.033 - (8.98 of 6.01) = ? of (46.09 - 20.98)
5466.97 - 3245.01 + 1122.99 = ? + 2309.99
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)