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    Question

    A circle touches all four sides of a quadrilateral ABCD.

    If AB = 18 cm, BC = 21 cm and AD = 15 cm, then length CD is:
    A 16 cm Correct Answer Incorrect Answer
    B 14 cm Correct Answer Incorrect Answer
    C 12 cm Correct Answer Incorrect Answer
    D 18 cm Correct Answer Incorrect Answer

    Solution

    If we have a circle onside the quadrilateral, then sum of the opposite side of Quadrilateral is equal. So, AD + BC = AB + CD 15 + 21 = 18 + CD 36 = 18 + CD CD = 18 cm

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