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    Question

    The product of the two numbers is 1500 and their HCF is

    10. The number of such possible pairs is/are:
    A 1 Correct Answer Incorrect Answer
    B 3 Correct Answer Incorrect Answer
    C 4 Correct Answer Incorrect Answer
    D 2 Correct Answer Incorrect Answer

    Solution

    Let two numbers be 10x and 10y where, x and y are two co-prime to each other  According to the question, we have Product of two numbers = 1500 ⇒ (10x) × (10y) = 1500 ⇒ xy = 1500/100 ⇒ xy = 15 No. of possible pairs which are co-prime to each other is  ⇒ (15 × 1), (5 × 3) ∴ The number of possible pairs is 2.

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