Question
The difference of simple interest from two banks on
₹8,000 in 3 years is ₹800. If the rate of interest per annum in two banks are R1 and R2, then what is the value of R1 - R2? (Where R1 > R2)Solution
(8000 × R1 × 3)/100 - (8000 × R2 × 3)/100 = 800 (8000 × 3 )/100 (R1 - R2) = 8000 R1 - R2 = (800 × 100)/(8000 × 3) = 10/3 = 3(1/3)%
2660.03 ÷ 94.98 x 59.9 = ? + 20.32
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...Find the approximate value of Question mark(?). No need to find the exact value.
(519.79 ÷ 10.03) × (47.98 ÷ 6) + √(63.94) × 4.04 = ?
...447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
1131.98 + ? – 1125.04 = 1364.93 – 1168.01
11.11% of 1800.89 + 34.89 X 10.99 - 500.50 = ?
(3/7 of 1049.88 + 44.95% of 799.79) ÷ (√168.89 + 24.77% of 400.11) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
If a:(b+c) =3:9 and c:(a+b) =10:14 then find the value of b:(a+c)?