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Let the longest diagonal be d. 42 = 22 + (d/2)2 16 - 4 = d2/4 12 × 4 = d × d d = 4√3 Side of the equilatral triangle = 4√3 Area of the triangle = (√3/4) × a2 = (√3/4) × (4√3) × (4√3) Area of the triangle = 12√3 cm2
(0.04)-2.5= ?
If √35 = 5.9 find the value of
What is least number which when successively divided by 6, 4 and 4 leaves a remainder 5, 3 and 3 respectively?
If 100.13 = 14 and ( 0.1)x = 140, then what is the value of x.
(0.25) -1.5 = ?
(1.69) -1.5 = ?
(5⁴) 5 × (25³)³ = ?
(0.09) -1.5 = ?
If (9000) 5 = 59.049
(1.9) -2.5 = ?