There are 8 boys and 4 girls giving interview for a job. If three of them are selected, then what is the probability that one of the three is a girl and the other two are the boys?
Total Number of candidates = 12 Let ‘S’ be the Sample Space Then, n(S) = number of ways of three candidates who got selected n(S) = 12C3 = 220 Let ‘E’ be the event of 1 girl and 2 boys selected Therefore, n(E) = number of possibility of 1 girl out of 4 and 2 boys out of 8 n(E) = 4C1 × 8C2 = 4 × 28 = 112 Now the required Probability = 112/220 = 28/55
A) abject
B) Accretion
C) Litigant
D) Wretched
...A) Maverick
B) Paucity
C) Ostensible
D) Unfeigned
Sumit is one of those employees who ……. very sincere.
The social activist and teacher…………nominated for the Presidency.
Rashmi and Rahul’s father ………. not well.
____________ has changed my determination to achieve it and in fact, it is __________ than it was yesterday.
No sooner did the bell ring …….. the students dispersed.
Neither the Chief Guest nor the audience …… interested in the proceedings.
For the child, ________________ of you will replace ___________.
Piping Hot
