A bag contains 6 balls of which 3 are red and 3 are black. They are drawn successively without replacement. What is the probability that colors are alternate?
We can choose balls as black, red or red black alternately, Required probability = 2 × (3/6 × 3/5 × 2/4 × 2/3 × 1/2 × 1) = 1/10
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