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Total number of apples in the heap = n(S) = 600 Let E be the event of selecting a rotten apple from the heap. Number of outcomes favourable to E = n(E) P(E) = n(E)/n(S) 0.14 = n(E)/600 ⇒ n(E) = 600 × 0.14 ⇒ n(E) = 84 Therefore, the number of rotten apples in the heap = 84
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