Question
What is the probability that four A’s come
consecutively in the word ‘AMALGAMATION’Solution
Total number of words that can be formed from the letters of the word AMALGAMATION= 12!/(4! × 2!) When all the A’s are together then the number of words can be formed = 9!/2! Required Probability = 9!/2!/ 12!/(4!× 2!) =1/55
Complete the series by replacing the question mark (?).
Q331T, U442X, Y553A, ?
In a code language, 'FIG' is coded as 9, and 'PLUM' is coded as 16. How will 'GUAVA' be coded in the same language?
Which of the following terms will replace the question mark (?) in the given series?
DCZ, FFY, ?, JLW, LOV
Select the number that will replace the question mark (?) in the given number series.
146, 90, 56, 34, 22, ?
In a group of 102 students, Priya’s rank is 25th from the top and Kusum’s rank is 20th from the bottom. How many students are between Pri...
A, B, C, D, E, F, G and H are sitting around a square table not facing the centre. Some of them are sitting at the corners while some are sitting at the...
Which of the following numbers will replace the question mark (?) in the given series?
18, 27, 31, 43, 44, 59, 57, ?
KML : NPO :: CED : ?
In a certain code language, 'MENIAL' is coded as 'NIEAML' and 'INCOME' is coded as 'CONMIE'. What is the code for 'FOREGO' in the given code language?
Relevant for Exams:
