Question
Given that E and F are events such that P(E) = 0.8, P(F)
= 0.4 and P(E∩ F) = 0.2. Find P(F|E).Solution
Given P (E) = 0.8, P (F) = 0.4 and P (E ∩  F) = 0.2 We know that by the definition of conditional probability, P(A/B) = P(A ∩  B)/P(B) By substituting the values, we get = P(E|F) = P(E ∩ F)/P(F) = 0.2/0.4 = 2/4 = 1/2 And = P(F|E) = P(E ∩  F)/P(E) = 0.2/0.8 = 2/8 = 1/4
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