Question
A vessel contains 5 red, ‘x’ green and 3 blue
ribbons. If two ribbons are drawn from the vessel randomly, then the probability of getting a red and a green ribbon is 3/11. Find the value of x.Solution
Total number of ribbons = (x + 8) According to question; (xC1 × 5C1)/(x + 8)C2 = 3/11 2 × 5x/(x + 8)(x + 7) = 3/11 110x = 3 × (x2 + 15x + 56) 110x = 3x2 + 45x + 168 3x2 – 65x + 168 = 0 3x2 – 9x – 56x + 168 = 0 3x(x – 3) – 56(x – 3) = 0 (3x – 56)(x – 3) = 0 So, x = 56/3 or x = 3 Since number of ribbons can’t be in fraction Therefore, x = 3
Which of the following statements is/are correct regarding Government of India’s New Integrated Food Security Scheme?
A. This New Integrated...
Classification of a wilful defaulter occurs after how many months of an account becoming NPA?
Which of the following is a Palaeolithic site of archaeological importance in India?
Which of the following is the new alluvium deposited by floods in the Ganga Plain?
What is the role of the Attorney General of India?
Who was the first chairman of Finance Commission of India?
_________ article of the Indian constitution provides for the contingency fund of India?
Rating and Investment Information (R&I), often seen in the context of credit ratings, is based in which of the following countries?
As per the recent guidelines by the RBI for Housing Finance Companies, what is the maximum deposit duration?
Where would you find the Jarawa tribes?
