Start learning 50% faster. Sign in now
Numbers of bananas = Numbers of rotten bananas + Numbers of good bananas ∴ Total number of bananas = 134 + 20 = 154 bananas P(E) = (Number of favourable outcomes) / (Total number of outcomes) P(picking a good banana) = 134/154 = 67/77
Who sits second to the left of K1?
Who among the following person sits second to the left of F?
Who sits opposite to F?
What is the code of ‘always impossible’?
How many persons sit between D and B, when counted from the left of D?
Who among the following person sits opposite to F?
What is the distance between J and Q, when counted right of Q?