Total number of eggs in the basket = n(S) = 1050 Let E be the event of selecting a rotten egg from the basket. Number of outcomes favourable to E = n(E) P(E) = n(E)/n(S) 0.36 = n(E)/1050 ⇒ n(E) = 1050 × 0.36 ⇒ n(E) = 378 Therefore, the number of rotten eggs in the basket = 378
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