Question
A bag contains 5 black balls,βaβ white balls and
βbβ purple balls. If one ball taken out from the bag, then probability of being it white is 2/7, while the probability of being purple is 5/14. The sum between number of white and purple balls in that bag is?Solution
Probability of white ball= a/(5 + a + b) a/(5 + a + b) = 2/7 5a β 2b = 10 β¦β¦β¦β¦(1) Probability of purple = b/(5 + a + b) = 5/14 9b β 5a = 25 β¦β¦β¦β¦.(2) From (1) and (2) we getΒ a = 4 b = 5 Therefore sum will be (a + b) = (4 + 5) = 9
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