Question
Tickets numbered 1 to 50 are mixed up and then a ticket
drawn at random. What is the probability that the ticket drawn bears a number which is multiple of 8?Solution
S= 1, 2, 3, 4 …………….. 50 = 50 E = Event of getting the multiple of 8 = 8, 16, 24, 32, 40 & 48 ∴ P (E) = `(n (E))/(n (S))`  = `(6)/(50)`  =  `(3)/(25)`
(350/?) = 23 + 33
(630 ÷ 35) × 2 + 144 = ? × 2
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
236.23-653.23+696.23=?
72 × 2 = ? + 104 – 14
36895 - 4256 - 2233 = ?Â
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)? = 15% of 2400 + 140% of 4200 – 12 3Â
√121 + √961− √289 =?2
