ATQ, Number of ways of selecting 3 coins from purse = 7C4 = {[7!/(4!×(7-4!))]} = {7!/(3!×4!)} = {(7×6×5)/(1×2×3)} = 35 Number of ways of selecting 3 five-rupees coins and 1 two-rupees coins = 4C3 × 3C1 = [(4!/(3!×1!)) × (3!/2!×1!)] = 4 × 3 = 12 Required probability =(12/35)
325934.78 + 78545.30 + 92.25 =?
7, 8, 12, 21, 37, ?
Find the value of 40 ÷ 5 of 6 × [3 ÷ 6 × (12 – 6)] – (15 ÷ 3 of 30):
242 + 18 × 8 – ? = 356
10 × 100 ÷ 5 + 9 = ?
(54/6) × 5 + 12 × (17/2) = ?% of 700
108 ÷ ? + 156 ÷ √144 = √64 × 2
Simplify the following expression:
(164-1)/17×15× (28+1)