Probability of A solving the puzzle = 3/5 Therefore the probability of A not solving the puzzle = 1- (3/5) = 2/5 Probability of B solving the puzzle = 2/3 Therefore. Probability of B not solving the puzzle = 1/3 Probability of C solving the puzzle = ¼ Probability of C not solving a puzzle= ¾ Therefore, required probability = { (3/5)*(2/3)*(¾)} + {(3/5)*(1/3)*(¼)}+{(2/5)*(2/3)*(¼)} 5/12
156, 182, 210, 240, 272, ?
9 14 38 129 ? 2705 16260
...What will come in place of the question mark (?) in the following series?
2, 5, 14, 41, 122, 365, ?
3 2 3 6 14 ? 115.5
728, 737, ?, 778, 814, 863
69, 35.5, 39.5, 68.25, 152.5, ?
24, 12, 18, 45, ?, 708.75
96 89 ? 90 94 91
...7 12 33 ? 635 3804
...15, 31, 67, 131, ?, 375
