Bag P will not have more number of balls than bag Q if we exclude the case where both the experiments result in placing Green balls in bag P. So, probability of bag P having total number of balls not more than Bag Q = 1 – Probability of getting (1 or 3 or 4 or 6) during both the experiments = 1 – 4/6 × 4/6 = 5/9
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