Question
A contains X green Balls, '7 Red Balls, and 5 Yellow
Balls. The probability to pick Green Ball at random is 3/5. Another Bag B contains ‘6 green Balls, ‘x – 3’ Yellow Balls and x - 4' Red Balls. If two balls are picked one after the other from Bag B at random then what is the probability for the Balls to be Red?Solution
x/(7+x+5) = 3/5 X = 18 Now, In Bag B: Red balls = 18 – 4 = 14 Yellow balls = 18 – 3 = 15 Green ball = 6 Required Probability = 14/35 × 15/35 = 6/35
Statements: E $ N, N * G, H % E
Conclusions: a) G # H b) H $ N
Statement: C < X ≤ B > E < L < I
Conclusion: I. X > L II. B > C
Statements: P # B, Q $ B, B @ J, J % F
Conclusions: I. F # B II. F @ B ...
Statement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > E II. H > K
...In the question, assuming the given statements to be true, find which of the following conclusion(s) among the three conclusions is/are true and then g...
Statements: L # W, W % V, V $ H, H # T
Conclusions : I. V @ T II. H & W III .V # T
...Statements: R % U, U # V, V @ C, C * F
Conclusions :
I. F $ V
II. C % U
III. R % F
IV. U #...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and then...
Statements: Q > M ≤ F < H; V = A > M > P; Z < I < P
Conclusions:
I. H ≥ Z
II. I < Q
III. V = I
Statements: D ≥ E > F; G < H ≤ F; H > I
Conclusions:
I. D > H
II. I < E
III. F > I
