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When two Dice are thrown simultaneously then – Total number of possible cases =62 =36 Number of favorable cases – (2,1) (3,1) (3,2) (4,1) (4,2) (4,3) (5,1) (5,2) (5,3) (5,4) (6,1) (6,2) (6,3) (6,4) (6,5) Total number of favorable cases = 15 Probability = 15/36 =5/12
16, 15, 24, -1, 48, ?
250 25 5 ? 0.6 0.3
52 83 114 ? 176 207
What will come in place of the question mark (?) in the following series?
4.5, 8, 15, 29, ?, 113
142, 148, 160, 178, ?, 232
380, ?, 360, 324, 260, 160
9 28 83 250 ? 2248
24, 8, 15, ?, 12, 4
80 81.5 83.5 ? 89 92.5
...12, 19, 32, ?, 76, 107