ATQ, Let the share of 'Bheem' be Rs. 'b' So, share of 'Amit' = Rs. (4200 - b) So, 4200 - b > 2b Or, 4200 > 3b So, 1400 > b Here, 'b' can take 1400 values i.e. from 0 to 1399. Now, since it is given that 'Amit' received more money than 'Bheem'. b < 4200 ÷ 2 Or, b < 2100 Here 'b' can take 2100 value i.e. from 0 to 2099. So, required probability = (1400/2100) = (2/3)
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