Total number of hats = 6 + 4 + 2 + 4 = 16 Let S be the sample space. Then, n(S) = number of ways of drawing 2 hats out of 16 = ¹⁶C_₂ = (16 × 15)/( 2 × 1) = 120 Let E= event of drawing all the hats are of green colour n(E) = ²C_₂ = 1 ∴ P (E) = (n(E))/(n(S)) = 1/120
(44.85% of 799.77 - √143.84)² ÷ (9/11 × 76.77) = ?
(2310.23 ÷ 32.98) + (1008.32 ÷ 23.9) + 1594.11 = ?
10.10% of 999.99 + 14.14 × 21.21 - 250.25 = ?
2660.03 ÷ 94.98 x 59.9 = ? + 20.32
(64.99% of 599.91 + 49.99% of 199.99 + 135.11) = ?2
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
83.781 `xx` 728.910 `-:` (3.008)2 = ?
`11(2/13)` + `5(2/11)` - `3(4/9)` = ?
(4913)1/3 × 10.11 × 13.97 ÷ 20.32 = ? + 39.022
√65 of 14.97 + √50 = (12.02)2 - ?