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Case (1) when student attempted 1 question from one section and from another, he attempted 3 questions Number of ways = 6C1 × 6C3 = 6 × 20 = 120 Case (2) when student attempted 2 questions from one section and from another, he attempted 2 questions Number of ways = 6C2 × 6C2 = 15 × 15 = 225 Case (3) when student attempted 3 questions from one section and from another, he attempted 1 question Number of ways = 6C1 × 6C3 = 6 × 20 = 120 N = 120 + 225 + 120 = 465 Required value = 465 – 64 =401
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