A student is required to answer 4 questions out of 12 questions in an English paper, which are divided into two sections of 6 questions each. If the student is not permitted to attempt more than 3 questions from either of the sections, then in ‘N’ number of ways can the student choose the 4 questions. Which of the following option/s will satisfy the value of (N-43)
Case (1) when student attempted 1 question from one section and from another, he attempted 3 questions Number of ways = 6C1 × 6C3 = 6 × 20 = 120 Case (2) when student attempted 2 questions from one section and from another, he attempted 2 questions Number of ways = 6C2 × 6C2 = 15 × 15 = 225 Case (3) when student attempted 3 questions from one section and from another, he attempted 1 question Number of ways = 6C1 × 6C3 = 6 × 20 = 120 N = 120 + 225 + 120 = 465 Required value = 465 – 64 =401
1672 ÷ 19 = ?% of 220
Solve: 3/4÷2/3
Find the value of 5342.5 +543.45+54.345 +5.4345+0.54345.
{(522 – 482 ) ÷ (27 + 73)} × 35 = ?% of 17
1200% of 18 + √1600 + 62 = ?2 + (90 of 0.4)
216% of 350 + 273 = ?2 × 21
What is (0.08% of 0.008% of 8)1/9 ?
1200 - 60 X 6 + 30 = 30 X 20 + ?
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶
(15 × 16) + 242= ? × 16