Question
Mohit is a teacher and he teach some students in two
(Morning & evening) slots. There are 5 boys and ‘x’ girls in morning slot, while there are ‘x’ boys and 8 girls in evening slot. If one student is chosen at random from any slot, then the probability of being girl is 5/9. Which of the following can be the value of ‘x’? I. 10 II. 4 III. 3 IV. 5 V. 6Solution
Probability for being girl from morning slot = (1/2) × (x/(x+5)) Probability for being girl from evening slot = (1/2) × (8/(x+8)) ATQ – 1/2 [x/(x+5)+(8/(x+8))]=5/9 10/9=(x(x+8)+8(x+5))/(x+8)(x+5)  10/9=(x2+8x+8x+40)/(x2+13x+40) 10x2+130x+400=9x2+144x+360 x2–14x+40=0 x2–10x–4x+40=0  x(x –10) –4(x –10)=0  x=10,4  So, both I and II follow
2660.03 ÷ 94.98 x 59.9 = ? + 20.32
What is the smallest integer that should be subtracted from 653 to make it divisible by both 23 and 27?
( 1000)1/3  × 10.11 × 4.97 ÷ 10.32 =? – 15.022
[(2/3 of 899.79) + 25% of 500.21] × (√195.77 + 30.03% of 399.79) = ?
15.232 + 19.98% of 539.99 = ? × 8.99
(29.98% of 9840) + ? + (19.899% of 8490) = 7560
 (1782 ÷ 11.98) ÷ 2.92 × 35.89 + 25% of 541 – 67% of 1299 = ?
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...What approximate value will replace the question mark (?) in the following?
39.99...
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
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