Question

    A bag contains 6 red, 10 yellow, and 14 black balls. If

    2 balls are picked at random without replacement, find the probability that the first ball is red and the second ball is either yellow or black.
    A 148/45 Correct Answer Incorrect Answer
    B 48/147 Correct Answer Incorrect Answer
    C 48/145 Correct Answer Incorrect Answer
    D 48/59 Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Total number of balls in the bag = 6 + 10 + 14 = 30 Case I: First ball is red and the second ball is yellow. Probability = (6/30) × (10/29) = 20/145 Case II: First ball is red and the second ball is black. Probability = (6/30) × (14/29) = 28/145 Required probability = (20/145) + (28/145) = 48/145

    Practice Next