A bag contains 7 green balls, 5 blue balls, and 10 yellow balls. A box contains 3 green balls and 8 yellow balls. A ball is randomly drawn from the box and put into the bag, and then a ball is randomly drawn from the bag. Find the probability that the ball is of yellow color.
ATQ, Case 1: Let the ball drawn from the box be yellow. Probability of drawing a yellow ball from the bag = 
Case 2: Let the ball drawn from the box be green. Probability of drawing a yellow ball from the bag = 
Therefore, required probability = 
Statements: H + L & F; F + V $ U; A * U * R
Conclusions:
I. H + U
II. A * F
III. R + L
Statements: J ≥ Q, L > S, L ≥ Q, K = J < N
Conclusion:
I. L > J
II. N > Q
Statements: U < P = I ≤ V < T ≤ R = W > H = Z > O
Conclusions:
I. U < W
II. R > O
Statements: J @ K, K $ L, L & M, M % N
Conclusions: I. K @ M II. N & J
...Statements: R % U, U # V, V @ C, C * F
Conclusions :
I. F $ V
II. C % U
III. R % F
IV. U...
Statements: J < K < M = L, D = E > F, F ≥ G < H = I > J
Conclusions:
I. D > K
II. I < L
III. E > J
Statements : T ≥ G; G > Z < Q ≥ P; P ≥ L < H = E
Conclusions :
I. Q > T
II. L ≤ Q
III. H > G
...Statements: L < M > P ≥ Q; N > O > M
Conclusions:
I. N ≥ Q
II. O > L
III. L = Q
Statement: P < Q; U < R > S; U < T > Q
Conclusion: I. S ≥ P II. P > S
Statement:
N > I ≥ H > O; O ≤ J ≤ K < F; H > P < C; C = R < S;
Conclusion:
I. I > C
II. P < F
III. H < S
