ATQ, Number of green bands in the box = 54 × (1/3) = 18 Remaining bands = 54 – 18 = 36 Let, number of yellow bands and red bands be 2b and b, respectively, Therefore, 2b + b = 36 3b = 36 b = 36/3 = 12 So, number of yellow bands = 2 × 12 = 24 Therefore, required probability = (24/54) = 4/9
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