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5C2 / (x + 14) C2= 10/153 [(5 * 4) / (1 * 2)] / [(x + 14) (x + 13) / (1 * 2)] = 10/153 (2 * 153) = x2 + 14x + 13x + 182 306 = x2 + 27x + 182 x2 + 27x - 124 = 0 x2 + 31x – 4x – 124 = 0 X(x + 31) – 4(x + 31) = 0 (x – 4) (x + 31) = 0 x = 4, -31 (negative value will be eliminated) Required difference = 7 – 5 = 2 balls
The variation in the restriction DNA fragment lengths between individuals of a species is called:
Which term describes the condition when the stamens and pistils of hermaphrodite flowers mature at different times, facilitating cross-pollination?
…………… method helps in maintaining high genetic variability in a population due to repeated intermating of heterozygous plants/populations.
...Term for the distance on a chromosome that permits one percent recombination (crossing over) between two linked genes is?
Number of Nuclei present in a pollen grain are :
………………………………. provides maximum opportunity for the breeder to use his skills for selection of desirable plants from segregating ...
In DNA fingerprinting large quantity of DNA (5-10 mg) is required and markers are ………………………
Which among the following factors is/are not essential for commercial exploitation of heterosis?
Which type of culture is described as growing in a liquid medium that is agitated to facilitate aeration and dissociation of cell clumps?
What term is used to describe a new plant produced through vegetative reproduction?