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Let S be the sample space. Then, n(S) = 52C2 = (52 x 51)/(2 x 1) = 1326 Let E = event of getting 1 ace and 1 queen. n(E) = number of ways of choosing 1 ace out of 4 and 1 queen out of 4 = 4C1x 4C1 = 4 x 4 = 16 Therefore, P (E) = (n(E))/(n(S)) = 16/1326 = 8/663
HCF and LCM of two positive numbers are 24 and 144. If one number is 50% more than the other number, then find the sum of both numbers
Find the total number of Prime factor in the given expression?
315× 56× 68
The LCM of two numbers is 40 times its HCF. If the product of the numbers is 1440, find their HCF.
Two numbers are in the ratio 3:5. The product of their H.C.F. and L.C.M. is 3375. The sum of the numbers is:
The HCF of two numbers is 21. Which of the following can never be their LCM?
Find the smallest two-digit number that leaves 4 as remainder when divided by 6 and 7.
The least number which when divided by 16, 32 and 48 leave remainder 4, 20 and 36 respectively is?
Let N be the greatest number that will divide 72, 105, 138 leaving the same remainder in each case. Then sum of the digits in N is: