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Let S be the sample space. Then, n(S) = 52C2 = (52 x 51)/(2 x 1) = 1326 Let E = event of getting 1 ace and 1 queen. n(E) = number of ways of choosing 1 ace out of 4 and 1 queen out of 4 = 4C1x 4C1 = 4 x 4 = 16 Therefore, P (E) = (n(E))/(n(S)) = 16/1326 = 8/663
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