Question
A costs thrice as much as B. A is sold at a loss of 15%
and B is sold at 7/5th of its price. If selling price of A is Rs. 2300 more than selling price of B, what is the cost price of A?Solution
Let the CP of B be 100x. CP of A = 3 × 100x = 300x Now SP of A = 85% of 300x = 255x And SP of B = 100x × 7/5 = 140x According to question, => 255x – 140x = 2300 => x = 20 CP of A = 300x = 300 × 20 = Rs. 6000
I.70x² - 143x + 72 = 0
II. 80 y² - 142y + 63 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
I. x2 = 10
II. y2 - 9y + 20 = 0
...I. 8x² - 78x + 169 = 0
II. 20y² - 117y + 169 = 0
I. x2 – 19x + 88 = 0
II. (y + 4)2 = 121
I. 3y2 + 13y - 16 = 0
II. 3x2 – 13x + 14 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I. 40x² + 81x + 35 = 0
II. 63y² + 103y + 42 = 0
I. 88x² - 13 x – 56 = 0
II. 15 y² + 41 y + 28 = 0