The cost price of article A and B is Rs. ‘X’ and Rs. (X + 750), respectively. Article A is sold at 20% profit while article B is sold at 10% loss. If selling price of article B is Rs. 120 more than that of article A and article B is sold after giving a discount of 20%, then find the marked price of article B.
Selling price of article ‘A’ = x × 120% = Rs. 1.2x Selling price of article ‘B’ = (x + 750) × 90% = Rs. 0.90x + 675 According to the question, 0.90x + 675 – 1.2x = 120 675 – 120 = 0.3x 0.3x = 555 x = 1850 Selling price of article ‘B’ = 0.90 × 1850 + 675 = Rs. 2340 Marked price of the article ‘B’ = 2600/90 × 100 = Rs. 1875
If n(A) = 25, n(B) = 40 and n(A ∪ B) = 50, then n(A ∩ B) equals
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