The ratio of the cost price and marked price of an article is 3:7, respectively. The article is sold after giving a discount of Rs. 800 such that there is a profit of 50%. Find the amount by which the article is marked up above its cost price.
Let the cost price and marked price of the article be Rs. 3x and Rs. 7x, respectively Therefore, selling price of the article = 1.5 × 3x = Rs. 4.5x According to the question, 7x – 4.5x = 800 Or, x = 800/2.5 = 320 Therefore, amount by which article is marked up above its cost price = 7x – 3x = 4x = Rs. 1280
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
I. 35x² + 83x + 36 = 0
II. 42y² + 53y + 15 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. x2 - 9x - 52 = 0
II. y2 - 16y + 63 = 0
I. 6x2- 47x + 77 =0
II. 6y2- 35y + 49 = 0
I. 3x2 - 14x + 15 = 0
II. 15y2- 34 y + 15 = 0
I. 15b2+ 26b + 8 = 0
II. 20a2+ 7a - 6 = 0
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. x²= 961
II. y= √961
If x^2 - 7x + k = 0 has roots that are equal, what is the value of k?
