A shopkeeper marked an article P% above its cost price and sold it for Rs. 1150 after giving a discount of 20%. If the shopkeeper had a loss of 8% on the whole transaction, then find the value of ‘P’. (approximate value)
Marked price of article = 1150/0.80 = Rs. 1437.5 Cost price of the article = 1150/0.92 = Rs. 1250 So, P = [(1437.5 - 1250)/1250] × 100 = 15% (approx)
(53 + 480 ÷ 4)% of 20 = ?% of 70
567-4824 ÷ 134 =? × 9
68% of 450 – 1008 ÷ 14 + 516 ÷ 43 =?
690 ÷ (75% of 460) = ? ÷ (50% of 160)
The sum of two numbers is 16 and their product is 63. The sum of their reciprocal is equal to:
√2401 × (√2116 ÷ 23) × 21 ÷ 3 = ?
(320 + 342 + 530 + 915) ÷ (20 + 22 – x + 18) = 43, then the value of x is:
7(3/6) of 534 + 262 = 61800 - ?
84% of 800 + 70% of 640 = 14 × ?
`sqrt(7744)` - `sqrt(4761)` + `sqrt(8281)` + `sqrt(5625)` + ? = 1856
