A shopkeeper marked an article P% above its cost price and sold it for Rs. 480 after giving a discount of 20%. If the ratio of cost price and selling price of the article is 25:30, respectively, then find the selling price if the article is sold at a profit of (P + 8)%.
Cost price of the article = (25/30) × 480 = Rs. 400 Marked price of the article = 480/0.8 = Rs. 600 P% = [(600 – 400)/400] × 100 = 50% Or, P = 50 Desired selling price = 400 × 1.58 = Rs. 632
Quantity I: The price of rice is decreased by 30%, by how much % the consumption is increase so that the expenditure will decreased by 10%?
Quant...
I. 4x2+ 25x + 36 =0
II. 2y2+ 5y + 3 = 0
I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
I. 2 x ² + x – 1 = 0
II. 2 y ² - 3 y + 1 = 0
...I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
I. 144x² - 163x - 65 = 0
II. 91y² - 128y -48 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
I. 5x + y = 37
II. 4y+ x = 15
