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Let, the cost price of the article be Rs. x According to the question, 500 – x = x – 300 Or, 2x = 800 Or, x = 400 Selling price of the product at profit of 25% = 400 × 1.25 = Rs. 500
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 499.87 – 24.95 × 14.04 + (20.15)²
(124.99)² = ?
? 3 + 95.06 X 39.87 ÷ 5.03 = 1271.89
Solve the given equation for ?. Find the approximate value.
[(49.88% of 320.11) × (34.85% of 460.24)] ÷ √783.94 = ?
(1440.13 ÷ 31.77) × (√168.69 + 16) - (24.87% of 719.99) = ?
Rice at Rs 80/kg is mixed with rice at Rs.40/ kg in a certain ratio such that by selling the mixture at Rs.60/ kg profit of 20% is made. If the quantity...
Find the approximate value of Question mark(?). No need to find the exact value.
59.88% of 419.78 + (24.09 × 5) ÷ 3 – √(80.81) = ?
...12.023 + 32.05 × 16.08 – 84.04% of 2400 = 56.06% of ?
20.02% of (95.96 × 104.01 – 56.02 × 64.04) – ? = 12.02 × 39.96 + 103.03
12.5% of 6400 + (17 × 25) = ?% of 2200+ 125
