Question
A seller marked an article 25% above its cost price and
sold it after giving a discount of Rs. 60. If the seller earned a profit of 20% in the transaction, then find the cost price (in Rs.) of the article.Solution
Let the cost price of the article = Rs. ‘100x’ Marked price of the article = 1.25 × (100x) = Rs. ‘125x’ Selling price of the article = Rs. ‘125x – 60’ According to the question, 1.20 × 100x = 125x – 60 Or, 125x – 120x = 60 Or, 5x = 60 Or, x = 12 Therefore, cost price of the article = 12 × 100 = Rs. 1200
I. 6x² + 37x + 45 = 0
II. 3y² - 11y + 6 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
I. 5x² -14x + 8 = 0 Â
II. 2y² + 17y + 36 = 0  Â
I. 63x2 + 148x + 77 = 0
II. 21y2 + 89y + 88 = 0
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
The equation x2 – px – 60 = 0, has two roots ‘a’ and ‘b’ such that (a – b) = 17 and p > 0. If a series starts with ‘p’ such...
I. 15y2 + 26y + 8 = 0
II. 20x2 + 7x – 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 37x² - 172x + 135 = 0
Equation 2: 29y² - 132y + ...
I. 2 x² - 15 + 18 = 0
II. x²- 3 + 2 = 0
...I. 2x2 – 5x – 12 = 0
II. 2y2 + 13y + 20 = 0
