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ATQ, Let, the cost price of 'Shirt' be Rs. '37a'. So, the profit on 'Shirt'= [(13/37) × 37a] = Rs. '13a' Therefore, selling price of 'Shirt' = 37a + 13a = Rs.'50a' Let, cost price of 'Pants' be Rs.'31p'. So, the loss incurred on 'Pants' = [(6/31) × 31p] = '6p' Therefore, selling price of 'pants' = 31 p 50a = 25p So, p = 2a So, loss incurred on 'Pants' = 6p = 6 × 2a = '12a' Therefore, 13a - 12a = 15 a = 15 So, selling price of 'Shirts' = Selling price of item 'Pants' = 50a = 50 × 15 = Rs. 750 So, sum of selling price of 'shirts' and item 'Pants' = 750 + 750 = Rs. 1,500
I. 5x² + 17x + 6 = 0
II. 2y² + 11y + 12 = 0
...I. 195x² - 46x - 21 = 0
II. 209y² + 7y - 12 = 0
I. 2 x² - 15 + 18 = 0
II. x²- 3 + 2 = 0
...The quadratic equation (p + 1)x 2 - 8(p + 1)x + 8(p + 16) = 0 (where p ≠ -1) has equal roots. find the value of p.
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 11x² - 93x + 88 = 0
Equation 2: 13y² + 118y + 93 = 0
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0