Question
The cost price of 6 chocolates and 4 biscuits amounts to
Rs. 6,960. Additionally, the cost price of 5 chocolates and 7 biscuits totals Rs. 8,880. Each chocolate and biscuit is marked up by 60% and 15%, respectively, and then sold with discounts of d% and Rs. 246, respectively. Despite these variations, the selling price of a chocolate and a biscuit remains the same. What is the value of 'd'?Solution
ATQ, Let the cost price of a chocolate = Rs. ‘x’ Let the cost price of a Biscuits = Rs. ‘a’ ATQ; 6x + 4a = Rs. 6960………………….(1) And, 5x + 7a = Rs. 8880………………..(2) Equation (2) × 6 – Equation (1) × 5, we get (5x + 7a) × 6 – (6x + 4a) × 5 = 8880 × 6 – 6960 × 5 30x + 42a – 30x – 20a = 53280 – 34800 Or, 22a = 18480 Or, a = 18480/22 = 840 Substituting this value ‘a’ in 6x + 4a = 6960 6x + 4 × (840) = 6960 Or, x = {(6960 – 3360)/6} = 3600/6 = 600 So, cost price of a Chocolate and a Biscuits are Rs. 600 and Rs. 840, respectively. Marked price of a Chocolates = 600 × (160/100) = Rs. 960 Marked price of a Biscuits = 840 × (115/100) = Rs. 966 Selling price of a Biscuits = Rs. 966 – 246 = Rs. 720 Therefore discount percentage on a Biscuits = d% = {(960 – 720)/960} × 100 Or, d% = (240/960) × 100 = 25% Or, d = 25
Statement: L > J ≥ U ≥ F; P < S < L
Conclusion: I. S < F II. P < U
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is/are definitely true and t...
Statements: H > E > I < F; D < I ≤ J; G < N ≤ D
Conclusions: Â
I. N < H Â
II. F ≥ G
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and the...
Statements: Q ≤ P ≤ R < S, T = M > Q > V
Conclusions: Â Â Â Â
 I. T > VÂ
II. Â V < SÂ
III. Q < TÂ
...Statements: B > C, D > E, C = F, A ≥ F, D = A
Conclusion:
I. B ≥ E
II. E > B
In these questions, relationship between different elements is shown in the statements. The statements are followed by conclusions.
Statements:...
Statements : E > N > W ≤ M > L; K ≥ G; L > P = Q > G
Conclusions :
I . M > G
II . W < N
III . L < K
...Statements: B > C; D > E = F < G ≥ H; C > I = D
Conclusions:
I. B < E
II. G > E
III. I < B
Statements:  T < U = S ≤  O, C > Y ≥ X, T > K = XÂ
Conclusions
I. O > K
II. C < T
III. U > K
Â
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