Question
A dishonest shopkeeper promises to sell his goods at 44%
loss, but he uses 910g weight instead of 1 kg. Find his actual loss percent?Solution
P =91-56=35 Loss % = (35/91) ×100 =38.4%
Between what values of x is the expression 19x - 2x2 - 35 positive?
I. 6x2 – 7x - 20 = 0
II. 3y2 - y - 14 = 0
I. 6x² - 23x + 7 = 0
II. 6y² - 29y + 9 = 0
The equation x2 – px – 60 = 0, has two roots ‘a’ and ‘b’ such that (a – b) = 17 and p > 0. If a series starts with ‘p’ such...
Quantity I: The cash price of a notebook is Rs. 100 but is can also be purchased on 11 monthly equal instalments of Rs. 10 each. Find rate of S.I.?
...I. 4x² - 15x + 9 = 0
II. 20y² - 23y + 6 = 0
If x and y satisfy x² + y² = 25 and x + y = 7, find xy.
I). p2 + 8p + 15 = 0
II). q2 + 9q + 20 = 0
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I. 6x2 - 47x + 77 =0
II. 6y2 - 35y + 49 = 0