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ATQ, Let cost price of the toy for shopkeeper = Rs. 100a Cost price of the toy for 'R' = 1.2 × 0.75 × 100a = Rs. 90a Cost price for 'S' = 1.2 × (90a + 80) According to question, 1.2 × (90a + 80) = 2040 108a + 96 = 2040 108a = 1944 a = 18 Original cost price of the toy = 18 × 100 = Rs. 1800
sin2 9 ° + sin2 10 ° + sin2 11 ° + sin2 12 ° + ……… + sin2 81 ° = ?
...If 4cos2x - 3 = 0, and (0° > x > 90°), then find the value of 'x'.
If tan θ = (2/√5), then determine the value of cos2 θ
If √3cosec 2x = 2, then the value of x:
If x = (sin 30 ° + cos 30 ° )/sec 60 ° , then find the value of 4x.
If sin3A = cos(5A-30°), then what is the value of A? Given that 3A is an acute angle.
If sin x + cos x = √2 sin x, then the value of sin x - cos x is:
Simplify the given equation: