Question
A shopkeeper purchased three items 'X', 'Y', and 'Z' at
the same price. He sold item 'X' at a 10% profit, item 'Y' at a 15% loss, and item 'Z' at a 30% profit. If he earns an overall profit of Rs. 570, then find the selling price of item 'Y'.Solution
ATQ, Let the cost price of each item be Rs. '100z'. So, the total cost price of 'X', 'Y' and 'Z' together = 3 X 100z = Rs. '300z' ATQ, (0.10 - 0.15 + 0.30) X 100z = 570 Or, 'z' = (570/25) = 22.8 Therefore, the selling price of 'Y' = 0.85 X 100z = 85 X 22.8 = Rs. 1938
If a = radic;( 3/2) , then radic; (1+a) + radic; (1-a) = ?
...If (6000) 5 = 7.776Â
(64/25)? × (125/512) ? - 1  = 5/8
(0.36) -1.5 = ?
What should come in place of the question mark (?) in the following questions?
417/414Â Â = Â Â ?
If √60 = 7.7 find the value of
(0.09)Â -1.5Â = ?
If 100.9Â = 12 and ( 0.1)x = 120, then what is the value of x.
(0.04) -2.5 = ?
If (5000) 5 = 3.125Â