Question
Suman bought two articles for Rs. 540. She sold one at a
loss of 10% and another at a profit of 10%. If the selling price of both the articles is equal, then find the difference between their cost prices.Solution
ATQ, Let the cost price of the two articles be Rs. x and Rs. y respectively. Selling price of the first article = 0.90 × x = Rs. 0.90x Selling price of the other article = 1.10 × y = Rs. 1.10y According to the question, 0.90x = 1.10y x/y = 1.10/0.90 = 11/9 Desired difference = (11 – 9)/20 × 540 = 0.10 × 540 = Rs. 54
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