A bag of cost price of Rs. 9000 is marked up by a certain percentage, and a discount percent of twice the markup percent is offered on it. If there is a loss of 10% in the transaction, then find the discount percent offered?
ATQ, Selling price of the bag = 0.90 × 9000 = Rs. 8100 Let the markup percentage be x% and the discount percentage offered be 2x%. Therefore, Marked price = 9000 + x% of 9000 = Rs. (9000 + 90x) Discount = 2x% of (9000 + 90x) Therefore, selling price = 9000 + 90x – 180x = 8100 Or, x2+ 90x – 900 = 0 On solving, x = −90 and 10 Therefore, Discount percentage = 2x=20%.
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