'Amit' purchased 'x' articles at the rate of Rs. 80 per article. He sold the articles such that 1st article is sold for Rs. 2, 2nd article is sold for Rs. 4, 3rd is sold for Rs. 6, and so on. He earned an overall profit of 50%. If considering a certain case in which 'Bunti' purchased (x + 6) articles for Rs. 40 each and sold all the articles at the profit of 80%, then find the selling price of all the articles sold by 'Bunti' in this particular case.
According to the question, Cost price of 'x' articles = Rs. 80x Selling price of last article = 2 X x = Rs. '2x' {Since, selling price of first article is Rs. 2, second article is Rs. '4', third article is Rs. '6'} Now, 2 + 4 + 6 + .... + 2x = 1.5 X 80x Or, 2(1 + 2 + 3 + .... + x) = 120x Or, (2/2) X {x(x + 1) } = 120x Or, x2Â + x = 120x Or, x2Â - 119x = 0 Or, x(x - 119) = 0 Or, x = 119 Therefore, number of articles purchased by 'Bunti' = (x + 6) = 125 Required selling price = 1.8 x 125 x 40 = Rs. 9000
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