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According to the question Let the cost price of each bag, each shoe, and each hat be Rs. ‘u’ Selling price of each bag = (270/9) = Rs. 30 Selling price of each shoe = (720/12) = Rs. 60 According to the question, (30–u)/u×100=k…… (I) Also, (60–u)/u×100=l…… (II) Dividing equation (I) by (II), we get (30–u)/(60–u)=k/l Or, (30–u)/(60–u)=k/7k Or, 210u–7u=60–u Or, 6u=60 Or, u=10 Therefore, the cost price of all the hats = Rs. 15u = Rs. 150 Required profit = 450 – 150 = Rs. 300
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