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ATQ, Let the cost price of the article be Rs. 'C'. Profit earned = Rs. (4,800 - C) Loss incurred = Rs. (C - 3,200) ATQ; 4,800 - C = (5/8) X (C - 3,200) Or, 8 X (4,800 - C) = 5 X (C - 3,200) Or, 38,400 - 8C = 5C - 16,000 Or, 13C = 54,400 So, 'C' = 4,184.62 Required selling price = (125/100) X 4,184.62 = Rs. 5,230.77
sin2 9 ° + sin2 10 ° + sin2 11 ° + sin2 12 ° + ……… + sin2 81 ° = ?
...If 4cos2x - 3 = 0, and (0° > x > 90°), then find the value of 'x'.
If tan θ = (2/√5), then determine the value of cos2 θ
If √3cosec 2x = 2, then the value of x:
If x = (sin 30 ° + cos 30 ° )/sec 60 ° , then find the value of 4x.
If sin3A = cos(5A-30°), then what is the value of A? Given that 3A is an acute angle.
If sin x + cos x = √2 sin x, then the value of sin x - cos x is:
Simplify the given equation: