Question
Sushil sold an item at 6% profit. Had he sold it for Rs.
5,760 less, he would have incurred a loss of 10%. Find the cost price of the item.ÂSolution
Let, the cost price of the item be Rs. '100x'. Initial selling price of the item = 1.06 X 100x = Rs. '106x' ATQ, 106x - 5760 = 0.9 X 100x Or, 106x - 5760 = 90x Or, 16x = 5760 Or, x = (5760/16) = 360 So, the cost price of the item = 100x = 100 x 360 = Rs. 36,000
I. 2x2 - 9 x + 9 = 0Â
II. 2y2 - 7 y + 3 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 2x² - 15x  + 13 = 0
II. 3y² - 6y + 3 = 0
I. x²= 961Â
II. y= √961
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
I. 27x6-152x3+125=0
II. 216y6Â -91y3+8=0
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
Relevant for Exams:
