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Let cost piece of on article is Rs. x Cost price of second article = Rs. ‘1500 – x’ According to question; 1.15 × x + 0.80 × (1500 – x) = 1480 Or, 1.15x – 0.8x = 1480 – 1200 Or, 0.35x = 280 Or, x = 800 Cost price of another article = 1500 – 800 = Rs. 700 Desired difference = 800 – 700 = Rs. 100 Hence, option b.
sin2 9 ° + sin2 10 ° + sin2 11 ° + sin2 12 ° + ……… + sin2 81 ° = ?
...If 4cos2x - 3 = 0, and (0° > x > 90°), then find the value of 'x'.
If tan θ = (2/√5), then determine the value of cos2 θ
If √3cosec 2x = 2, then the value of x:
If x = (sin 30 ° + cos 30 ° )/sec 60 ° , then find the value of 4x.
If sin3A = cos(5A-30°), then what is the value of A? Given that 3A is an acute angle.
If sin x + cos x = √2 sin x, then the value of sin x - cos x is:
Simplify the given equation: