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Let the cost price of the article be Rs. '100x' So, selling price of the article = '100x' X 1.1 = Rs. '110x' ATQ: Marked price of the article X 0.9 = Rs. '110x' Or, marked price of the article = '110x' ÷ 0.9 = Rs. '122.22x' ≈ Rs. '122x' Now, Profit received when no discount was given = '122x' - '100x' = Rs. '22x' Required profit percentage = (22x/100x) X 100 = 22%
sin2 9 ° + sin2 10 ° + sin2 11 ° + sin2 12 ° + ……… + sin2 81 ° = ?
...If 4cos2x - 3 = 0, and (0° > x > 90°), then find the value of 'x'.
If tan θ = (2/√5), then determine the value of cos2 θ
If √3cosec 2x = 2, then the value of x:
If x = (sin 30 ° + cos 30 ° )/sec 60 ° , then find the value of 4x.
If sin3A = cos(5A-30°), then what is the value of A? Given that 3A is an acute angle.
If sin x + cos x = √2 sin x, then the value of sin x - cos x is:
Simplify the given equation: